How do spatial multipliers work?

  • This topic is empty.
Viewing 2 posts - 1 through 2 (of 2 total)
  • Author
    Posts
  • #1684
    mhemstrommhemstrom
    Participant

    I’m using spatial multipliers to model specific fuel break locations. The fuel breaks are two 90m pixels wide (along roads). If I set the multiplier for high severity wildfire at 0.1, does that mean that the chance of fire going through the fuel break is 0.1*0.1 or 0.01? I suspect the probability is higher than that because fire could move in any of 3 ways through the fuel break (direct plus 2 diagonals). How exactly does this work?

    #1850
    leonardo-fridleonardo-frid
    Keymaster

    The probability of a fire crossing a fuelbreak will depend on a number of factors inluding:

     

    1. The configuration of the fuel break and how it relates to the surrounding cells and their probabilities for fire
    2. The ultimate length of the fire perimeter that abuts against the fuel break, a longer perimeter means that there are more opportunities for crossing
    3. Whether you are using direction and or slope multipliers and the relation of the fuel break to the fire source with respect to these.

     

    In the example you give, assuming the fire is a single pixel in size and it is trying to grow by a single pixel only, that all cells surrounding that pixel are equal aside from the fuel break, and that three/eight fuel break cells are adjacent to the source cell, the probability of the fire crossing the fuel break will be:

     

    [the sum over fuel break neighbors (relative probability/relative distance from source)]

    divided by

    [the sum over all neighbors (relative probability/relative distance from source)]

    where the relative probability for 3 fuel break cells is 0.1 and 1 for 5 other cells, relative distance is 1 for horizontal/vertical neighbors and the square root of 2 for diagonal neighbors.  In this case the probability of a fuel break cell burning is 0.05186.

     

Viewing 2 posts - 1 through 2 (of 2 total)
  • You must be logged in to reply to this topic.